Question

2.35*10^-4M,,Mg(OH)2

what is the pH of this solution

Answer 1

Mg(OH)2 ==>Mg^2+ + 2OH^-

2.35E-4M = [Mg(OH)2]
(Mg^2+) = 2.35E-4
(OH^-) = 2*2.35E-4
pOH = 4.70E-4
pH + pOH = pKw = 14
You know pOH and pKw, solve or pH.