Posted by Kensey on Monday, June 18, 2012 at 7:08pm.
Since the skier is pulled at a constant speed, the pulling force (for one skier)is given by:
F = m*g[sin theta + mu_k*cos theta]
= 80*10[sin25+0.15*cos25]
= 446.8N (along the incline upwards)
Work done by F in moving distance of 230m:
W=F*x = 446.8*230 =102,776 Joules
Power reqd for this work:
P= W/time = 102,776J/138s = 745 watts = 1HP(approx.)
So for 30 skiers, engine power required = 30HP
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