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December 18, 2014

December 18, 2014

Posted by **Henry** on Monday, June 18, 2012 at 6:12pm.

- Calculus -
**Reiny**, Monday, June 18, 2012 at 8:53pmlet x=0, y=0, then z= -2 ---> (0,0,-2)

let x=1, y=0, then z = -1/3 -- (1,0,-1/3)

let two of the variables be anything you want, then solve for the third.

- Henry --- Calculus -
**Reiny**, Monday, June 18, 2012 at 8:57pmJust noticed that you had posted this before and Steve had answered you.

Please check your earlier posts before re-posting the same question again, to avoid unnecessary duplication of our efforts.

http://www.jiskha.com/display.cgi?id=1339787586

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