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March 27, 2017

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Differentiate each function

a) y = -3x^2 + 5x - 4

b) f(x) = 6/x - 3/(x^2)

c) f(x) = (3x^2 - 4x)(x^3 + 1)

the answers i got for each was:

a) y'= -6x + 5

b) f'(x)= -6/x^2 + 6/x^3

c) f'(x)= 15x^4 + 6x - 16x^3 - 4

please double check and let me know if these are correct, thank you.

  • Calculus - please check my work - ,

    All correct, well done!

  • Calculus - please check my work - ,

    thank you! can u help me on this question please

    determine the coordinates of two points on the plane with equation 5x + 4y - 3z = 6

  • Calculus - please check my work - ,

    Any point on the plane will satisfy the equation.

    Since there are three variables x,y and z, you can fix any two variables and solve for the third.

    Example:
    Assuming arbitrarily y=6, z=6
    =>
    5x+4(6)-3(6)=6
    5x+24-18=6
    5x=0
    x=0
    So (0,6,6) is a point on the plane.

  • Calculus - please check my work - ,

    thank you

  • Calculus - :) - ,

    You're welcome!

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