Posted by **lora** on Monday, June 18, 2012 at 5:21pm.

a ball dropped off a cliff and took 3.59s to fall to the water below. neglecting air resistance how far in meters did it fall how far is it down to water

- physical science -
**Elena**, Tuesday, June 19, 2012 at 9:21am
v=vₒ-g•t

at the top point

0= vₒ-g•t1,

t1= vₒ/g =34.7/9.8=3.54 s.

h= vₒ•t1 –g•t1²/2=34.7•3.54 - 9.8•3.54²/2 =61.5 m

h=g•t2²/2,

t2=sqrt(2•h/g) =

=sqrt(2•61.5 /9.8) = 3.54 s.

Time upward =time downward!

t =2•t1=2•3.54 =7.08 s.

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