Posted by lora on Monday, June 18, 2012 at 5:21pm.
a ball dropped off a cliff and took 3.59s to fall to the water below. neglecting air resistance how far in meters did it fall how far is it down to water

physical science  Elena, Tuesday, June 19, 2012 at 9:21am
v=vₒg•t
at the top point
0= vₒg•t1,
t1= vₒ/g =34.7/9.8=3.54 s.
h= vₒ•t1 –g•t1²/2=34.7•3.54  9.8•3.54²/2 =61.5 m
h=g•t2²/2,
t2=sqrt(2•h/g) =
=sqrt(2•61.5 /9.8) = 3.54 s.
Time upward =time downward!
t =2•t1=2•3.54 =7.08 s.
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