Posted by RJ on .
Find the value of the derivative of y=sin^2(0.25x^4) at the point (ð,0.17)

Math 
Steve,
y' = 2sin(.25x^4)*cos(.25x^4)*(x^3)
= x^3 sin(.5x^4)
not sure what your angle is. Solving for x when y=0.17 didn't give me a useful value.