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physical science

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if a ball is thrown straight up at a speed of 34.7m/s how long in seconds will it continue to rise before it starts to fall back down?

  • physical science -

    Upward motion:
    v=vₒ-g•t
    at the top point
    0= vₒ-g•t1,
    t1= vₒ/g =34.7/9.8=3.54 s.
    h= vₒ•t1 –g•t1²/2=34.7•3.54 - 9.8•3.54²/2 =61.5 m
    Downward motion
    h=g•t2²/2,
    t2=sqrt(2•h/g) =
    =sqrt(2•61.5 /9.8) = 3.54 s.
    Time (upward) =time (downward)!
    t =2•t1=2•3.54 =7.08 s.

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