Two waves travel in the same medium at the same speed. One has wavelength 0.0382 m and frequency 9.67×106 Hz. The other has wavelength 0.0486 m. What is the period of the second wave?

Speed(of first wave) = freq*wavelength (m/s)

Speed of the second wave is also the same. Since its wavelength is given, find the frequency. Reciprocal of the frequency is the time period in secs.

Amotorcycle slowed down to rest from avelocity of 10m\sec whiletraveling 30m what is its average acceleration

Motorcycle slowed down to rest from avelocity of 10 m\sec while traveling 30 m what

To find the period of a wave, we can use the formula:

Period (T) = 1 / Frequency (f)

We are given the wavelength of the second wave (0.0486 m), but we need to find the frequency of the second wave before we can calculate the period.

The speed of a wave in a medium is given by the equation:

Speed (v) = Frequency (f) × Wavelength (λ)

Since both waves travel at the same speed, we can set up the equation:

Speed of the first wave = Speed of the second wave

Frequency of the first wave × Wavelength of the first wave = Frequency of the second wave × Wavelength of the second wave

(9.67×10^6 Hz) × (0.0382 m) = Frequency of the second wave × (0.0486 m)

Now we can solve for the frequency of the second wave:

Frequency of the second wave = (9.67×10^6 Hz) × (0.0382 m) / (0.0486 m)

Frequency of the second wave ≈ 7.615×10^6 Hz

Now that we have the frequency of the second wave, we can calculate the period:

Period (T) = 1 / Frequency (f)

Period (T) ≈ 1 / (7.615×10^6 Hz)

The period of the second wave is approximately equal to 1.314×10^(-7) seconds.