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September 2, 2014

September 2, 2014

Posted by **Randy** on Sunday, June 17, 2012 at 9:34pm.

- Homework test -
**Reiny**, Sunday, June 17, 2012 at 9:52pmUse

amount = c (1/2)^(t/k), where k is the half-life period

so ....

.7 = 1(1/2)^(t/5730)

.7 = (2)^(-t/5730)

ln .7 = ln ( 2^(-t/5730) )

ln .7 = -t/5730 (ln2)

-t/5730 = ln .7/ln 2 = -.514573...

t = 2948.5 years

or 2900 to the nearest 100 years

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