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September 1, 2014

September 1, 2014

Posted by **Mike Joseph** on Sunday, June 17, 2012 at 7:55pm.

If the car is traveling at 98 km/h, how much friction force will be required?

I cannot figure out how to solve this problem. Someone please help me?

- Physics -
**Elena**, Monday, June 18, 2012 at 3:09amΣFy = N• cos θ − mg − f •sin θ = 0

ΣFx = N• sin θ + f •cos θ = m•v²/R,

where f –friction force

Solving the 1st equation for N, we obtain

N =( f •sin θ + m•g)/cos θ,

Substitute N to the 2nd equation and obtain friction force

f =m[(v²•cosθ/R) - g•sinθ].

f=1400[27²•cos14/57 – 9.8•sin18} =

=1400[12.4-2.04] =14000 N

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