Posted by Mike Joseph on Sunday, June 17, 2012 at 7:55pm.
ΣFy = N• cos θ − mg − f •sin θ = 0
ΣFx = N• sin θ + f •cos θ = m•v²/R,
where f –friction force
Solving the 1st equation for N, we obtain
N =( f •sin θ + m•g)/cos θ,
Substitute N to the 2nd equation and obtain friction force
f =m[(v²•cosθ/R) - g•sinθ].
f=1400[27²•cos14/57 – 9.8•sin18} =
=1400[12.4-2.04] =14000 N
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