Tension = T
force up = T
force down = m g
m g - T = m a
torque = I * angular acceleration
T * R = I alpha = I a/R
but I for disk = (1/2) m R^2
T R = (1/2) m R a
T = (1/2) m a interesting :)
m g - (1/2) m a = m a
g = (3/2) a
a = (2/3) g
T = (1/2) m (2/3) g = (1/3) m g
= 1.63 N or B
T-tension, M –torque,
I = mR²/2 -moment of inertia of disc
I•a/R = T•R,
m•2T/m = mg-T,
T=mg/3 =0.5•9.8/3 = 1.63
Answer this Question
physics - A toy top consists of a rod with a diameter of 13.00 mm and a disk of ...
physics - A string is wrapped around a uniform disk of mass M = 1.6 kg and ...
physics - A thin, light string is wrapped around the rim of a 4.00kg solid ...
Physics - A small disk of radius R1 is mounted coaxially with a larger disk of ...
physics - A thin, light horizontal string is wrapped around the rim of a 4.00-kg...
physics 101 - A solid uniform disk of mass 21kg and radius 85cm is at rest flat ...
Physics - A 15 kg uniform disk of radius R = 0.25 m has a string wrapped around ...
Physics - what are the forces acting on a string that is wounded around a ...
PHYSICS - An irregularly shaped plastic plate with uniform thickness and density...
mechanics - A string is wound around a uniform disk of radius R and mass M. The ...