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Posted by Anonymous on Sunday, June 17, 2012 at 5:31pm.

Let an angle in quad IV such that cos= 2/5 find exact value of csc and cot

you have a 2-√21-5 triangle, so in QIV, you have cos = 2/5 csc = -5/√21 cot = cos*csc = -2/√21

tits

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