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February 28, 2015

February 28, 2015

Posted by **Christine** on Sunday, June 17, 2012 at 5:21pm.

- Physics -
**Damon**, Sunday, June 17, 2012 at 5:53pmF = m A

m g sin theta = m a = -m d^2 x/dt^2

g sin theta = -d^x/dt^2

for small Theta sin Theta = theta = x/L

g x/L = -d^x/dt^2

let x = c sin 2 pi f t

then v = dx/dt = 2 pif c cos 2 pi f t

and a = d^2x/dt^2 = - (2 pi f)^2 c sin 2 pi f t

so

g /L = (2 pi f)^2

2 pi f = sqrt (g/L)

but T = period = 1/f

so

T = 2 pi sqrt (L/g)

1.87 = 2 pi sqrt(L/9.81)

sqrt(L/9.81) = .2976

L/9.81 = .088577

L = .869 meter

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