Tuesday

September 2, 2014

September 2, 2014

Posted by **Kyla** on Sunday, June 17, 2012 at 3:06pm.

- Physics -
**Count Iblis**, Sunday, June 17, 2012 at 4:21pmThe potential energy increase is:

W = - M m G/(2R) + M m G/R

where M is the mass of the Earth, m is the mass of the object and R is the Earth's radius and G is the gravitational constant.

We can simplify the expression for W:

W = 1/2 M m G/R = m R/2 (M G /R^2) =

m R/2 g = 2.82*10^10 J

**Answer this Question**

**Related Questions**

Physics - How much energy is required to move a 900 kg object from the Earth's ...

physics - How much work is required to lift a 600-kg satellite to an altitude of...

Physics - Calculate the percentage of Earth’s gravitational force on the ISS ...

Physics - In the rough approximation that the density of the Earth is uniform ...

phys - An astronaut drops an object from rest (relative to the planet) on a ...

Algebra - The gravitational force between an object & the Earth is inversely ...

physics - Assuming the Earth's magnetic field averages about 0.50×10−4 T ...

Gravitation help..........thanks - A projectile is shot directly away from Earth...

physics - Two Earth satellites, A and B, each of mass m, are to be launched into...

physics - what is the value of the acceleration due to gravity of the earth at ...