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October 1, 2014

October 1, 2014

Posted by **Tom** on Sunday, June 17, 2012 at 1:32pm.

- Calculus -
**MathMate**, Monday, June 18, 2012 at 8:22amWhat do you want to do with the equation?

Do you need to differentiate the right-hand-side?

Treat it as a product of cos(3x) and sin³(x) and within each, use the chain rule.

dy/dx=-3sin(3x)sin³(x)+cos(3x)*3cos²(x)

and simplify.

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