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Calculus

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evaluate the limit:

lim cos(x + pi/2)/x
x->0

  • Calculus - ,

    cos(x+pi/2)
    = cosx cos pi/2 - sinx sin pi/2
    = 0 - sinx
    = -sinx

    so
    limit cos(x+pi/2)/x as x----> o
    = lim -sinx/x , x ---> 0
    = -1

    using the fact that lim sinx/x = 1

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