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an arrow is shot into air. its range is 200m and its time of flight is 5s . if g=10m/s2 ,then horizontl compoent of velocity and the mximum height will be

  • science - ,

    1. R = Xo * T = 200 m.
    Xo*5 = 200
    Xo = 40 m/s. = Hor. component of initial
    velocity.

    2. Tr = T/2 = 5 / 2 = 2.5 s.

    Y = Yo + gt.
    Yo = Y - gt = 0 - (-10)*2.5 = 25 m/s. =
    Ver. component of initial velocity.

    hmax = (Y^2-Yo^2)/2g.
    hmax = (0-(25)^2) / -19.6 = 31.9 m.

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