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October 21, 2014

October 21, 2014

Posted by **ashu** on Sunday, June 17, 2012 at 5:38am.

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1.68 m/s away from the observer

2.96 m/s away from the observer

- physics -
**Elena**, Sunday, June 17, 2012 at 5:46pm{f(observed) - f(source)}/f(observed) = 20/100, u = 340 m/s

At source approaching

f(observed) = [v/(v-u)] •f(source),

v =[f(obs)-f(sour)] •u/ f(obs) = 20% •340/100%= 68 m/s.

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