Thursday
March 23, 2017

Post a New Question

Posted by on Sunday, June 17, 2012 at 2:00am.

1) How much longer would it take for light to travel through 1.0 km of water than 1.0 km of air?
What formula do you use? The answer is 1.1 x 10^-6 s

2) The acetate roll on overhead projector is placed at a distance 1.2f from the lens. (where f is the focal length). At what distance should the screen be placed to properly focus the image?
Why is the answer 6f?

  • Physics - , Sunday, June 17, 2012 at 4:43am

    1
    c /v(water) = n - refractive index (for water n=1.33)
    v =c/n = 3•10^8/1.33=2.26•10^8 m/s
    t1=s/c=1000/3•10^8=3.3•10^-6 s.
    t2=s/v=1000/2.26•10^8=4.4 •10^-6 s.
    t2-t1 =(4.4 -3.3) •10^-6 = 1.1•10^-6 s
    2
    1/f=1/di+1/do
    di=f•do/(do-f) =
    =f•1.2f/(1.2f-f)=
    =1.2f²/0.2f = 6f

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question