Posted by **rachel** on Saturday, June 16, 2012 at 11:38pm.

the area under the curve y= square root of 9-x^2 with coordinates x=-3 and 3 , find the volume rotated aroudn the x-axis

- calculus -
**Reiny**, Saturday, June 16, 2012 at 11:52pm
Hey, that's just the top half of the circle

x^2 + y^2 = 9 rotated, giving us the whole sphere

radius is 3,so the volume is (4/3)π(3^3) = 36π

But I guess you want it done using integration....

volume π∫(9-x^2) dx from -3 to 3

= π[9x - (1/3)x^3] from -3 to 3

= π(27 - 9 - (-27 + 9))

= 36π

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