Posted by **rachel** on Saturday, June 16, 2012 at 11:38pm.

the area under the curve y= square root of 9-x^2 with coordinates x=-3 and 3 , find the volume rotated aroudn the x-axis

- calculus -
**Reiny**, Saturday, June 16, 2012 at 11:52pm
Hey, that's just the top half of the circle

x^2 + y^2 = 9 rotated, giving us the whole sphere

radius is 3,so the volume is (4/3)π(3^3) = 36π

But I guess you want it done using integration....

volume π∫(9-x^2) dx from -3 to 3

= π[9x - (1/3)x^3] from -3 to 3

= π(27 - 9 - (-27 + 9))

= 36π

## Answer This Question

## Related Questions

- Calculus - 1. Find the area of the region bounded by the curves and lines y=e^x ...
- calculus - Find the volume if the area between the curve y=lnx, x=1, and y=1 is ...
- Calculus - Let R be the region bounded by y=6sin((pi/2)x), y=6(x-2)^2, y=3x+3 ...
- Calculus AB - Please help me with this WS 1) Find the value of lim as x-->-(...
- calculus, volume , application of integration - show steps for the following: ...
- calculus - The region A is bounded by the curve y=x^2-5x+6 and the line y = -x...
- Calculus - Volume created when the area bounded by the curve y = 1/x, the x-axis...
- Calculus - *Note I reposted this question as I changed the subject** The Region...
- calculus - The area enclosed between the x-axis, the curve y=x(2-x) and the ...
- calculus - The area enclosed between the x-axis, the curve y=x(2-x) and the ...

More Related Questions