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March 29, 2015

March 29, 2015

Posted by **Huhu.** on Saturday, June 16, 2012 at 10:39pm.

A3.7 m/s

B0.18 m/s

C5.2 m/s

D13 m/s

E0.13 m/s

- Physics -
**Elena**, Sunday, June 17, 2012 at 3:43pmPE(max) = KE +PE

kx(max)²/2 =mv²/2 +kx²/2

x(max) = sqrt(mv²/k +x²)=

=sqrt(0.25•9/200 +0.15²)=0.184.

v(max) = ω•x(max) = x(max) •sqrt(k/m) =

=0.184•sqrt(200/0.25)=5.2 m/s

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