Posted by James on Saturday, June 16, 2012 at 9:50pm.
say mass is area (density would cancel)
original mass = pi R^2 with center at x = 0
mass of cutout = pi R^2/9 with center at x = (2/3)R
mass of remaining = 8 pi R^2/9 with center at x
8 pi R^2/9 * x + pi R^2/9 * 2R/3 = pi R^2 * 0
8 x = - 2 R/3
x = - R/12 yes E
How is it known that the mass of the cutout is centered at (2/3)R?
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