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October 26, 2014

October 26, 2014

Posted by **Tom** on Saturday, June 16, 2012 at 9:09pm.

- Calculus -
**Reiny**, Saturday, June 16, 2012 at 11:38pmWe know one direction vector of the plane is (-2,3,1)

We have to find another.

Use the two points (3,5,1) and (1,2,3)

the vector would be (2,3,-2)

I will assume you know how to find the cross-product between these two vectors.

I got (9,2,12)

So the plane has equation

9x + 2y + 12z = c

plug in (1,2,3)

9 + 4 + 36 = c = 49

scalar equation is

9x + 2y + 12z = 49

vector equation is

r = (3,5,1) + t(-2,3,1) + s(2,3,-2)

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