Posted by Ray on Saturday, June 16, 2012 at 7:44pm.
u=36 m/s, v(o)= -20 m/s.
Imagine that the bat is at rest, and the ball is approaching to it at the releative velocity
v(x)= v(o)+u =20+36 =56 m/s.
Then in the bat’s frame of reference the ball bounces at the velocity 56 m/s directed in opposite direction. The velocity of the ball in the rigid frame is the sum of the relative velocity of the bounce and velocity of the moving frame of reference.
The projections on the x-axis;
v(x) = 2u(x) –v(ox),
u(x) = u.
v(ox) = -v(o) ,
v(x) = 2u+v(o)
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