Posted by **Joe** on Saturday, June 16, 2012 at 7:43pm.

The density of a 5.0-m long rod can be described by the linear density function λ(x) = 145 g/m + 14.2x g/m2. One end of the rod is positioned at x = 0 and the other at x = 5 m.

a) Determine the total mass of the rod.

b) Determine the center-of-mass coordinate.

- Physics - Center of Mass -
**Elena**, Sunday, June 17, 2012 at 8:51am
m=∫ρ•dx =∫(145+14.2x) •dx =

= ∫145•dx+∫14.2•x•dx =

=145•x + 14.2x²/2=

=145•5 + 14.2•25/2 =902.5 g.

Calculate the integral

∫ρ•x•dx =

=∫(145+14.2x) •x •dx =

= ∫145•x•dx+∫14.2•x²•dx =

=145•x²/2 + 14.2x³/3=

=145•25/2 + 14.2•125/3=2404.2 kg.

x(c/m/) =∫ρ•x•dx/∫ρ•dx =2404.2/902.5=2.66 m.

C.M. (2.66 m; 0)

- Question -
**Hayden**, Monday, March 18, 2013 at 9:27pm
Question: Shouldn't the 2404.2 be in grams and not Kg?

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