Posted by Newman on Saturday, June 16, 2012 at 7:41pm.
The coordinates of the checkers
1(6;14)
2 (14;22)
3(22;10
4(30;30)
5(16;16) checkerboard
x(cm) = {m•6+m•14+m•22+m•30+M•16}/{4•m+M} =
={72•19+16•120}/4•19+120 =16.78 cm,
y(cm) = {m•14+m•22+m•10+m•30+M•16}/{4•m+M} =
={76•19+16•120}/4•19+120 =17.16 cm.
C.M. (16.78; 17.16)
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