Sunday

April 20, 2014

April 20, 2014

Posted by **Newman** on Saturday, June 16, 2012 at 7:41pm.

- Physics - Center of Mass -
**Elena**, Sunday, June 17, 2012 at 8:45amThe coordinates of the checkers

1(6;14)

2 (14;22)

3(22;10

4(30;30)

5(16;16) checkerboard

x(cm) = {m•6+m•14+m•22+m•30+M•16}/{4•m+M} =

={72•19+16•120}/4•19+120 =16.78 cm,

y(cm) = {m•14+m•22+m•10+m•30+M•16}/{4•m+M} =

={76•19+16•120}/4•19+120 =17.16 cm.

C.M. (16.78; 17.16)

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