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April 18, 2015

April 18, 2015

Posted by **Laura** on Saturday, June 16, 2012 at 7:04pm.

Here a question:

Calculate the standard free-energy change for the following reaction at 25 ¡ÆC

2Au^+3(aq) + 3Cr(s) ¡ê 2Au(s) + 3Cr^+2(aq)

- chemistry -
**DrBob222**, Saturday, June 16, 2012 at 7:33pmWhat you want to do is to calculate Eocell. You get Eocell from

Au^3+ + 3e ==> Au Eo = ? and

Cr ==> Cr^3+ + 3e Eo = ?

Add Eo for the Au (as written) to Eo for Cr (as written).

Then delta Go = -nEocell*F

n will be 6, F is 96,485 and Eocell is from above.

- chemistry -
**Laura**, Saturday, June 16, 2012 at 7:51pmOk I got it. I got the correct answer. Thank you so much for explain how to start and for your help.

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