Posted by Mike Joseph on Saturday, June 16, 2012 at 5:20pm.
Let the x-axis point toward the center of curvature and the y-axis point upward. Use Newton’s second law
ΣFy = N• cos θ = mg, N
ΣFx = N• sin θ = m•v²/R,
Dividing the 2nd equation by the 1st equation, we obtain
tan θ = v² /R•g
v=sqrt(R•g•tan θ)=sqrt(57•9.8•tan14)=11.8 m/s,
V = 98 km/h =98000/3600 =27.2 m/s
V>v => the friction force is required (directed to the center of the curvature)
Related Questions
Physics - A 1400-kg car rounds a curve of 57-m banked at an angle of 14 degrees...
Physics - A 1400 kg car rounds a curve of 57 m banked at an angle of 14 degree ...
Physics - A car, having a mass of 1.2 x 10^3kg rounds a curve which is banked at...
physics - A 2100 kg car rounds a curve of 67 m banked at an angle of 13. If the ...
Physics - Hi everyone, finished all my utexas physics homework, save this last ...
Physics - Hi everyone, finished all my utexas physics homework, save this last ...
physics - Two banked curves have the same radius. Curve A is banked at an angle ...
Physics - Two banked curves have the same radius. Curve A is banked at an angle ...
Physics - Two banked curves have the same radius. Curve A is banked at an angle ...
PHYSICS - A highway curve with a radius of 750 m is banked properly for a car ...
For Further Reading
