Posted by Claire Holt on Friday, June 15, 2012 at 9:09pm.
A skier traveling 11.0 m/s reaches the foot of a steady upward 19.6° incline and glides 13.8 m up along this slope before coming to rest. What was the average coefficient of friction?

physics  Anonymous, Tuesday, April 5, 2016 at 11:45pm
Use equation mgh + mgh(initial) = 1/2mv^2  1/2 mv(initial) + W

physics  Khai Lim, Saturday, October 22, 2016 at 10:11pm
KE = PE + W_friction
1/2 * mv^2 = mgh + mu*mgcos(theta)d
 m is cancel out
 sin(theta) = heigh/ distance( inclide) ===> h = d*sin(theta)
1/2 v^2 = g (d*sin(theta)) + mu* (g*cos(theta))*d
now you can solve for mu ^^ Good luck.
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