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October 25, 2014

October 25, 2014

Posted by **daniel** on Friday, June 15, 2012 at 7:48pm.

- physics -
**Damon**, Friday, June 15, 2012 at 9:03pmthey both go at the same horizontal speed forever and ever (until they hit)

Therefore we only have to solve a dropping problem

h and 4 h and we want the times in the air

h = (1/2) g t^2

4 h = (1/2) g T^2

t^2 = 2 h/g

T^2 = 8 h/g

T^2/t^2 = 4

so

T/t = 2

so the high one is in the air twice as long

so

It goes twice as far.

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