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March 31, 2015

March 31, 2015

Posted by **Hannah** on Friday, June 15, 2012 at 1:39pm.

I need to calculate the temperature.

390 X 1 X 100-t / 2 = 420 X 1 X t-20 / 1

Is this how I would set it up to solve for the temp?

Thank you.

- Physics(Please respond) -
**drwls**, Friday, June 15, 2012 at 2:12pmWhat are your 390 and 420 "values" and what are their units?

What temperature are you solving for? is this supposed to be a steady state problem?

- Physics(Please respond) -
**Elena**, Friday, June 15, 2012 at 3:14pmI believe that 390 is the coefficient of thermal conductivity "κ" from

dQ/dt = κ•A•dT/dx.

The units of "κ" are watts/K• meters. Its value for cooper is 390.

As for the rest I'm in complete accord with drwls: what temperature ....

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