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July 29, 2014

July 29, 2014

Posted by **Sarah** on Friday, June 15, 2012 at 12:13am.

a) y = -3x^2 + 5x - 4

b) f(x) = 6/x - 3/(x^2)

c) f(x) = (3x^2 - 4x)(x^3 + 1)

thank you in advance :)

- Calculus -
**Damon**, Friday, June 15, 2012 at 2:57amNow wait a minute, you try first.

- Calculus -
**Henry**, Monday, June 18, 2012 at 5:47pmis it

a) y'= -6x + 5

b) f'(x)= -6/x^2 + 6/x^3

c) f'(x)= 15x^4 + 6x - 16x^3 - 4

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