The diameter of a wrecking ball used to tear down buildings is 3.5 ft. What is the volume (to the nearest hundredth)?
Is there enough information given?
Do I use formuls of v=4/3*pi*r(squared)
Hope it makes sense
It's r cubed.
http://www.aaastudy.com/exp79_x8.htm
Yes, there is enough information given to calculate the volume of the wrecking ball. In order to find the volume, you can indeed use the formula for the volume of a sphere, which is V = (4/3) * π * r^3, where r is the radius of the sphere.
However, since the diameter (the distance across the wrecking ball) is given instead of the radius, you need to start by finding the radius (r). The radius is simply half of the diameter, so r = 3.5 ft / 2 = 1.75 ft.
Now that you have the radius, you can substitute it into the formula to calculate the volume (V) of the wrecking ball. Since we want the volume to the nearest hundredth, you will need to round your answer to the nearest hundredth.
V = (4/3) * π * (1.75 ft)^3
Using the value of π as approximately 3.14159, calculate the expression inside the parentheses first:
V ≈ (4/3) * 3.14159 * (1.75 ft)^3
V ≈ (4/3) * 3.14159 * (1.75 ft * 1.75 ft * 1.75 ft)
Then simplify the expression:
V ≈ (4/3) * 3.14159 * 5.796875 ft^3
V ≈ 38.48528125 ft^3
Finally, round the volume to the nearest hundredth:
V ≈ 38.49 ft^3
Therefore, the volume of the wrecking ball is approximately 38.49 ft^3.