Posted by **bri** on Thursday, June 14, 2012 at 3:26pm.

What would be the final concentration if 175mL of a 0.45M solution of sodium sulfite Na2SO3 are added to 650mL of water?

Please reply with the steps on how to do this question so I can learn. I can't find examples or anything related in my textbooks and I take it via correspondence, so no class instructor to ask for help. Thank you

- Chemistry -
**DrBob222**, Thursday, June 14, 2012 at 5:07pm
First, one must assume the volumes are additive; i.e., that 175 mL of the acid adds to 650 mL of water to give a total volume of 175+650 = 825.0 mL. In general volumes are not additive but the error in this assumption is small enough to be neglected.

I do these this way.

0.45M x (175/850) = ? M.

You may prefer to use the dilution formula which is

M1V1 = M2V2

0.45*125 = M2*850

Solve for M2.

Often in this kind of problem you are given the TOTAL volume of V2; remember that you don't have anything to add if the total volume is given.

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