Posted by **monea** on Thursday, June 14, 2012 at 3:15pm.

Let x be the number of courses for which a randomly selected student at a certain university is registered. The probability distribution of x appears in the table shown below:

x 1 2 3 4 5 6 7

p(x) .04 .05 .08 .26 .39 .16 .02

(a) What is P(x = 4)?

P(x = 4) =

(b) What is P(x 4)?

P(x 4) =

(c) What is the probability that the selected student is taking at most five courses?

P(at most 5 courses) =

(d) What is the probability that the selected student is taking at least five courses? more than five courses?

P(at least 5 courses) =

P(more than 5 courses) =

(e) Calculate P(3 x 6) and P(3 < x < 6).

P(3 x 6) =

P(3 < x < 6) =

- statistics -
**MathMate**, Thursday, June 14, 2012 at 4:56pm
Given probability distribution (pdf):

x 1 2 3 4 5 6 7

p(x) .04 .05 .08 .26 .39 .16 .02

Since ∑p(x) for x=1 to 7 =1.0

we conclude that:

p(0)=0

p(1)=0.04

...

p(7)=0.02

p(8+)=0

(a)

P(x=4)=0.26/1=0.26

(b)

P(x>4)

=P(5)+P(6)+P(7)+P(8+)

=0.39+0.16+0.02+0

=0.53

(c)

P(x≤5)=P(0-)+P(1)+P(2)+P(3)+P(4)+P(5)

=?

(d) P(x≥5)=P(x>4)

(e)

P(3≤x≤6)=P(3)+P(4)+P(5)+P(6)

P(3<x<6)=P(4)+P(5)

- statistics -
**Anonymous**, Sunday, May 10, 2015 at 8:17pm
Fifty students are polled on the courses they are taking, and X is the number of courses a student takes. The number of courses ranges from 2 to 6. Is the following a probability distribution of X?

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