Physics
posted by Ethan on .
At a county fair, a boy takes his teddy bear on the giant Ferris wheel. Unfortunately, at the top of the ride, he accidentally drops his stuffed buddy. The wheel has a diameter of 14.6 m, the bottom of the wheel is 2.4 m above the ground and its rim is moving at a speed of 1.0 m/s. How far from the base of the Ferris wheel will the teddy bear land?

H=D+h= 14.6+2.4 =17 m.
H=gt²/2
t=sqrt(2H/g) =sqrt(2•17/9.8)=1.86 s.
v(x) =1 m/s.
L=v(x) •t=1•1.86 = 1.86 m.