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October 21, 2014

October 21, 2014

Posted by **Mike** on Thursday, June 14, 2012 at 11:49am.

If the car is traveling at 98-km/h (27-m/s), will a friction force be required? If so in what direction?

How much friction force will be required?

- Physics -
**Elena**, Thursday, June 14, 2012 at 1:07pmLet the x-axis point toward the center of curvature and the y-axis point upward. Use Newton’s second law.

ΣFy = N• cosθ − mg − f •sinθ = 0 ...(1)

ΣFx = N• sinθ + f •cosθ = m•v²/R,....(2)

Solving the 1st equation for N, we obtain

N =( f •sin θ + m•g)/cos θ,

Substitute N to the 2nd equation and obtain friction force

f =m[(v²•cosθ/R) - g•sinθ].

- Physics -
**darabee**, Saturday, April 5, 2014 at 1:17amf=[fy.fx].N

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