Posted by **Katie** on Wednesday, June 13, 2012 at 4:21pm.

What is the area of a regular pentagon with a side length of 10 inches and a distance from the center to a vertex of 10 inches?

Round your answer to the nearest tenth.

- geometry -
**Reiny**, Wednesday, June 13, 2012 at 5:07pm
Look at one of the five isosceles triangle

each has a 72 degree angle with sides of 10 containing that angle.

Use the cosine law to find the base of that triangle

x^2 = 10^2 + 10^2 - 2(10)(10)cos 72

x = ...

Once you have that, find the area of the triangle (1/2)(10)(10sin(above angle)

then multiply by 5

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