Posted by Melissa on Wednesday, June 13, 2012 at 4:00pm.
v = at = -9.8(.333) = -3.26
s = 6.06 - 4.9t^2
when it hits, s=0, so
0 = 6.06 - 4.9t^2
t = 1.11
The speed at t = 0.333 s is
V = (g/2) t^2
It hits the ground when (g/2) t^2 = 6.06 m
Solve for that new t.
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