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Posted by Melissa on Wednesday, June 13, 2012 at 4:00pm.

An object falls from the top of the school, which is 6.06m high. Assume air resistance can be ignored and the acceleration is 9.8m/s^2 If the object was dropped( not thrown) , what is its speed after 0.333s How long does it take to hit the ground

v = at = -9.8(.333) = -3.26 s = 6.06 - 4.9t^2 when it hits, s=0, so 0 = 6.06 - 4.9t^2 t = 1.11

The speed at t = 0.333 s is V = (g/2) t^2 It hits the ground when (g/2) t^2 = 6.06 m Solve for that new t.

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