math
posted by dan on .
Find the sum of the arithmetic progression
4 + 9 + 14 + 19 + …….94 + 99 + 104

first you have to know how many terms you have
what term is 104
a + (n1)d = term(n)
4 + (n1)(5) = 104
5n  5 = 100
5n = 105
n = 21
now sum(21) = (first + last)(21/2)
=(4+104)(21/2) = 1134