Posted by **Andre** on Wednesday, June 13, 2012 at 1:33pm.

The distance needed to stop a car (d) varies directly with the aquare of the speed of the car (s). If a car traveling 25 mph requires 0 feet to stop, how many feet will be required to stop a car that is traveling at 60 mph?

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**Reiny**, Wednesday, June 13, 2012 at 2:30pm
d = k v^2

when v=25, d= 0 ????

you see to have a typo .

suppose you meant to type d=50

then

50 = k(25)^2

k = 50/625 = 1/25

d = (1/25) v^2

so when v= 60

d = (1/25)(3600) = 144

Once you have determined what your typo was, replace the 50 in my solution with the correct value of d

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**malekah**, Wednesday, February 26, 2014 at 2:44am
the stopping distance D varies directly with the square of the speed S. if a car traveling 50mph has a stopping distance of 250 feet, find the stopping distance of 60mph.

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**Anonymous**, Wednesday, September 16, 2015 at 3:01pm
What is k in this solution

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**Anonymous**, Thursday, November 26, 2015 at 6:27pm
300

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