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March 1, 2015

March 1, 2015

Posted by **Andre** on Wednesday, June 13, 2012 at 1:33pm.

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**Reiny**, Wednesday, June 13, 2012 at 2:30pmd = k v^2

when v=25, d= 0 ????

you see to have a typo .

suppose you meant to type d=50

then

50 = k(25)^2

k = 50/625 = 1/25

d = (1/25) v^2

so when v= 60

d = (1/25)(3600) = 144

Once you have determined what your typo was, replace the 50 in my solution with the correct value of d

- Math Models -
**malekah**, Wednesday, February 26, 2014 at 2:44amthe stopping distance D varies directly with the square of the speed S. if a car traveling 50mph has a stopping distance of 250 feet, find the stopping distance of 60mph.

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