Posted by Please Help! on Wednesday, June 13, 2012 at 12:56pm.
log4(x-2)(x+1) = 1
(x-2)(x+1) = 4
x^2 - x - 6 = 0
(x-3)(x+2)
x = 3 or -2
however, x = -2 does not fit the original equation, since log of negative numbers are not defined.
So, the only solution is x=3
Related Questions
Logarithms - Solve log4 x + log4(x-2)=log4(15) I know how do the example in my ...
Algebra 2 - Simplify: 1. 2log10^5+log10^4 2. 2log3^6-log3^4 3. log4^40-log4^5 4...
Algebra II - Solve, round to four decimal places if necessary: log4(x-9)=2 ...
Math - solve for x: log4 X - log4 2 = 2 log(2x) = 2 Now what do I do?
Math(Please check) - solve for x: log4 X - log4 2 = 2 log(2x) = 2 Now what do I ...
math - Solve the equation algebraically. Round the result to three decimal ...
Math - Evaluate the expression without using a calculator: log4(2)= ____? Use a ...
Trig/Pre-Calc - Could someone please help me on this problem. I'm really ...
algebra II logarithms - f(x)=log4 (x)+3 how could i get this so i could graph it...
college algebra... LOG - log4(little 4) 8 how do i write this in y=?
For Further Reading