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March 3, 2015

March 3, 2015

Posted by **Please Help!** on Wednesday, June 13, 2012 at 12:56pm.

- Algebra 2 -
**Steve**, Wednesday, June 13, 2012 at 1:16pmlog

_{4}(x-2)(x+1) = 1

(x-2)(x+1) = 4

x^2 - x - 6 = 0

(x-3)(x+2)

x = 3 or -2

however, x = -2 does not fit the original equation, since log of negative numbers are not defined.

So, the only solution is x=3

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