Algebra 2
posted by Please Help! on .
log4 (x2)  log4 (x+1) = 1

log_{4}(x2)(x+1) = 1
(x2)(x+1) = 4
x^2  x  6 = 0
(x3)(x+2)
x = 3 or 2
however, x = 2 does not fit the original equation, since log of negative numbers are not defined.
So, the only solution is x=3