Posted by **Please Help!** on Wednesday, June 13, 2012 at 12:56pm.

log4 (x-2) - log4 (x+1) = 1

- Algebra 2 -
**Steve**, Wednesday, June 13, 2012 at 1:16pm
log_{4}(x-2)(x+1) = 1

(x-2)(x+1) = 4

x^2 - x - 6 = 0

(x-3)(x+2)

x = 3 or -2

however, x = -2 does not fit the original equation, since log of negative numbers are not defined.

So, the only solution is x=3

## Answer this Question

## Related Questions

- Logarithms - Solve log4 x + log4(x-2)=log4(15) I know how do the example in my ...
- Algebra 2 - Simplify: 1. 2log10^5+log10^4 2. 2log3^6-log3^4 3. log4^40-log4^5 4...
- Algebra II - Solve, round to four decimal places if necessary: log4(x-9)=2 ...
- precalc - I don't understand how to do these w/o calc. I tried to write it in a ...
- Math(Please check) - solve for x: log4 X - log4 2 = 2 log(2x) = 2 Now what do I ...
- Math - solve for x: log4 X - log4 2 = 2 log(2x) = 2 Now what do I do?
- math - Solve the equation algebraically. Round the result to three decimal ...
- Logarithm help - Write each expression as a single logarithm I need help really...
- Math - Evaluate the expression without using a calculator: log4(2)= ____? Use a ...
- math - log4(2x+4)-3 =log4 3

More Related Questions