Posted by **Mike ** on Wednesday, June 13, 2012 at 11:38am.

A 0.140 kg baseball traveling 39.0 m/s strikes the catchers mitt, which, in bringing the ball to rest, recoils backward 13 cm. What is the average force applied by the ball on the glove?

- Physics -
**Elena**, Wednesday, June 13, 2012 at 3:09pm
Physics - drwls, Monday, June 11, 2012 at 1:24pm

Use this formula:

Force x distance = work done against mitt = Kinetic Energy change

Which leads to:

Force = (1/2)M V^2/d

If you want to start from F = m*a, you have to use an equation for the acceleration, a

a = V/t = v/[d/(v/2)] = v^2/(2d)

F = m*V^2/(2d)

## Answer this Question

## Related Questions

- Physics - A 0.140 kg baseball traveling 39.0 m/s strikes the catchers mitt, ...
- Physics 6A - A 0.140- baseball traveling 34.0 strikes the catcher's mitt, which...
- Physical - A 0.140-kg baseball traveling 38.0m/s strikes the catcher's mitt, ...
- Physics - A 0.133 kg baseball traveling 30.6 m/s strikes the catcher's mitt, ...
- Physics - A 0.140-kg baseball traveling 39.0 m/s strikes the catcher's mitt, ...
- Physics - A 0.145-kg baseball traveling 35.0 m/s strikes the catcher's mitt ...
- physics - A 0.180 kg baseball, traveling 32.0 m/s, strikes the catcher's mitt, ...
- physics - A 0.110 kg baseball, traveling 32.0 m/s, strikes the catcher's mitt, ...
- Physics - A 0.130 kg baseball, traveling 35.0 m/s, strikes the catcher's mitt, ...
- Physics - A 0.130 kg baseball, traveling 35.0 m/s, strikes the catcher's mitt, ...

More Related Questions