posted by Mike on .
What is the magnitude of the average force required to stop an 1500 kg car in 8.0 s if the care is traveling at 95 km/h?
Sum of F = ma?
0= v(initial) –at
a= v(initial)/t =95000/3600•8=3.3 m/s²,
F(fr) =ma=1500•3.3=4948 N