Posted by Sara on Wednesday, June 13, 2012 at 2:06am.
If csc Ø = 13/12, the sinØ = 12/13
so we are dealing with the 12-5-13 right-angled triangle in II
then cosØ = -5/13
sin 2Ø = 2sinØcosØ
= 2(12/13)(-5/13)
= -120/169
cos 2Ø = cos^2 Ø - sin^2 Ø
= 25/169 - 144/169
= -119/169
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