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Posted by **Amanda** on Tuesday, June 12, 2012 at 9:46am.

Solve for rock's velocity as it hits the bottom of the hole.

&How long is the rock in the air, from the instant it is released until it hits the bottom of the hole?

- physics -
**drwls**, Tuesday, June 12, 2012 at 10:02am(1/2)M V2^2 = (1/2)MV1^2 + M g D

D is the depth of the hole.

V1 is the initial "toss" velocity

V2 is the velocity at the bottom of the hole.

Cancel out the M's and solve for V2.

For time in the air, solve the following equation for t:

Y = -13 = V1*t - (g/2)*t^2

g = 9.8 m/s^2

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