Posted by Anonymous on Tuesday, June 12, 2012 at 1:57am.
A=sum is odd
B=sum is 5 or less
P(B)=|{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)}|/36
=10/36
P(A∩B)=|{(1,1),(1,3),(2,1),(2,3),(3,2),(4,1)}|/36
=6/36
P(A|B)=P(A given B)
=P(A∩B)/P(B)
=?
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