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probability

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two dice are tossed. find the probability that the sum is odd given that the sum is 5 or less

  • probability - ,

    A=sum is odd
    B=sum is 5 or less

    P(B)=|{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)}|/36
    =10/36

    P(A∩B)=|{(1,1),(1,3),(2,1),(2,3),(3,2),(4,1)}|/36
    =6/36

    P(A|B)=P(A given B)
    =P(A∩B)/P(B)
    =?

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