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August 31, 2015
Posted by **Anonymous** on Tuesday, June 12, 2012 at 1:57am.

- probability -
**MathMate**, Tuesday, June 12, 2012 at 6:35amA=sum is odd

B=sum is 5 or less

P(B)=|{(1,1),(1,2),(1,3),(1,4),(2,1),(2,2),(2,3),(3,1),(3,2),(4,1)}|/36

=10/36

P(A∩B)=|{(1,1),(1,3),(2,1),(2,3),(3,2),(4,1)}|/36

=6/36

P(A|B)=P(A given B)

=P(A∩B)/P(B)

=?