if y=(x^2)/(x+4) find the values of x where there is a horizontal tangent
y = x^2/(x+4)
y' = x(x+8)/(x+4)^2
since the denominator is not zero for x =/= -4, we just need to find there the numerator is zero.
x = 0 or -8
y' = x(x+8)/(x+4)^2
since the denominator is not zero for x =/= -4, we just need to find there the numerator is zero.
x = 0 or -8