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October 23, 2014

October 23, 2014

Posted by **James** on Monday, June 11, 2012 at 7:14pm.

(a) Determine the total mass of the rod.

(b) Determine the center-of-mass coordinate.

I found the total mass of the rod to be 885 g, how does one find the center of mass coordinate in the x-direction given this information?

Thank you in advance.

- Physics -
**Elena**, Tuesday, June 12, 2012 at 4:38amm=∫ρ•dx =∫(140+14.8x) •dx =

= ∫140•dx+∫14.8•x•dx =

=140•x + 14.8x²/2=

=140•5 + 14.8•25/2 =885 g.

Calculate the integral

∫ρ•x•dx =

=∫(140+14.8x) •x •dx =

= ∫140•x•dx+∫14.8•x²•dx =

=140•x²/2 + 14.8x³/3=

=140•25/2 + 14.8•125/3=2367 kg.

x(c/m/) =∫ρ•x•dx/∫ρ•dx =2367/885=2.67 m.

C.M. (2.67 m; 0)

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