Friday

August 1, 2014

August 1, 2014

Posted by **Genny** on Monday, June 11, 2012 at 4:26pm.

v(t)=2t^2-8t+10

(A)

Use calculus to find her instantaneous acceleration at t=8.0seconds

(B)

Use calculus to find the area under the curve to see how far she traveled between t=0seconds and t=4.0seconds

Please walk me through all of your steps, instead of just suggesting a formula.

Thank you!

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